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Problem Calculate d d x [ x 2 tan x + sin x x + 1 ] \dfrac{d}{dx}\left[\dfrac{x^2\tan x+\sin x}{x+1}\right] d x d [ x + 1 x 2 tan x + sin x ] 2 x tan x + x 2 sec 2 x + cos x x + 1 \dfrac{2x\tan x + x^2\sec^2 x + \cos x}{x+1} x + 1 2 x tan x + x 2 sec 2 x + cos x ( 2 x tan x + x 2 sec x + cos x ) ( x + 1 ) − ( x 2 tan x + sin x ) ( x + 1 ) 2 \dfrac{\bigl(2x\tan x + x^2\sec x + \cos x\bigr)(x+1) - \bigl(x^2\tan x + \sin x\bigr)}{(x+1)^2} ( x + 1 ) 2 ( 2 x tan x + x 2 sec x + cos x ) ( x + 1 ) − ( x 2 tan x + sin x ) ( 2 x tan x + x 2 sec 2 x + cos x ) ( x + 1 ) − ( x 2 tan x + sin x ) ( x + 1 ) 2 \dfrac{\bigl(2x\tan x + x^2\sec^2 x + \cos x\bigr)(x+1) - \bigl(x^2\tan x + \sin x\bigr)}{(x+1)^2} ( x + 1 ) 2 ( 2 x tan x + x 2 sec 2 x + cos x ) ( x + 1 ) − ( x 2 tan x + sin x ) ( 2 x tan x + x 2 sec 2 x ) ( x + 1 ) − ( x 2 tan x + sin x ) ( x + 1 ) 2 \dfrac{\bigl(2x\tan x + x^2\sec^2 x\bigr)(x+1) - \bigl(x^2\tan x + \sin x\bigr)}{(x+1)^2} ( x + 1 ) 2 ( 2 x tan x + x 2 sec 2 x ) ( x + 1 ) − ( x 2 tan x + sin x ) Browse the problem library