Mathematics

Problem

For the function

y=\dfrac{(x^{2}+1)(4x-3)}{x+2}

, defined for

x\neq-2

, determine the slope of the tangent to the curve at

x=1

. a)

\dfrac{28}{3}

\dfrac{28}{9}

\dfrac{26}{9}

\dfrac{10}{3}