Physics

Problem

An object of mass

m

is suspended at the end of a massless wire of length

L

and area of cross-section,

A

. Young modulus of the material of the wire is

Y

. If the mass is pulled down slightly its frequency of oscillation along the vertical direction is: a.

f = \frac{1}{2\pi} \sqrt{\frac{mL}{YA}}

f = \frac{1}{2\pi} \sqrt{\frac{YA}{mL}}

f = \frac{1}{2\pi} \sqrt{\frac{mA}{YL}}

f = \frac{1}{2\pi} \sqrt{\frac{YL}{mA}}