Physics

Problem

A proton is accelerated from rest through a potential difference of

2.0\,\text{kV}

and then enters, at right angles, a uniform magnetic field of

0.20\,\text{T}

. The frequency with which it revolves in the field is closest to a)

4.8\times10^{5}\,\text{Hz}

3.0\times10^{6}\,\text{Hz}

1.6\times10^{7}\,\text{Hz}

7.5\times10^{6}\,\text{Hz}