Mathematics

Mathematics

Problem

PQRSPQRS is a cyclic quadrilateral such that PRPR is a diameter of the circle. If ∠QPR=67∘\angle QPR = 67^\circ and ∠SPR=72∘\angle SPR = 72^\circ, then ∠QRS=\angle QRS = \_\_\_\_\_\_. (A) 41∘41^\circ (B) 23∘23^\circ (C) 67∘67^\circ (D) 18∘18^\circ

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