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Mathematics
Problem
If
x
=
e
2
t
x=e^{2t}
x
=
e
2
t
and
y
=
ln
(
1
+
t
)
y=\ln(1+t)
y
=
ln
(
1
+
t
)
, then
d
y
d
x
\dfrac{dy}{dx}
d
x
d
y
in terms of
t
t
t
equals a)
2
e
2
t
1
+
t
\dfrac{2e^{2t}}{1+t}
1
+
t
2
e
2
t
b)
1
2
e
t
(
1
+
t
)
\dfrac{1}{2e^{t}(1+t)}
2
e
t
(
1
+
t
)
1
c)
1
2
e
2
t
(
1
+
t
)
\dfrac{1}{2e^{2t}(1+t)}
2
e
2
t
(
1
+
t
)
1
d)
1
e
2
t
(
1
+
t
)
\dfrac{1}{e^{2t}(1+t)}
e
2
t
(
1
+
t
)
1
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