Mathematics

Mathematics

Problem

Points A,B,CA, B, C lie on a circle with centre OO such that AB=ACAB = AC. The radius AOAO is produced to meet the circle again at DD. If ∠BAC=42∘\angle BAC = 42^{\circ}, then ∠ADC\angle ADC equals a) 90∘90^{\circ} b) 48∘48^{\circ} c) 69∘69^{\circ} d) 96∘96^{\circ}

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