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Mathematics
Problem
Consider
p
(
x
)
=
∣
x
−
5
∣
x
−
5
p(x)=\dfrac{|x-5|}{x-5}
p
(
x
)
=
x
−
5
∣
x
−
5∣
and the values listed near
x
=
5
x=5
x
=
5
. x : 5.1 5.01 5.001 p(x): 1 1 1 x : 4.9 4.99 4.999 p(x): –1 –1 –1 Find the right-hand limit
lim
x
→
5
+
p
(
x
)
\displaystyle \lim_{x\to5^{+}}p(x)
x
→
5
+
lim
p
(
x
)
. a)
−
1
-1
−
1
b)
0
0
0
c)
1
1
1
d) The limit does not exist
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