Problem

Problem

Find the percentage error in specific resistance given by ρ=πr2Rl\rho = \frac{\pi r^2 R}{l} where rr is the radius having value (0.2±0.02) cm(0.2 \pm 0.02) \text{ cm} , RR is the resistance of (60±2) ohm(60 \pm 2) \text{ ohm} and ll is the length of (150±0.1) cm(150 \pm 0.1) \text{ cm} .

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