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Mathematics
Mathematics
Problem
If
∫
x
2
e
−
2
x
d
x
=
e
−
2
x
(
a
x
2
+
b
x
+
c
)
+
d
\int x^2 e^{-2x}\,dx = e^{-2x}(ax^2 + bx + c) + d
∫
x
2
e
−
2
x
d
x
=
e
−
2
x
(
a
x
2
+
b
x
+
c
)
+
d
, then (a)
a
=
1
a = 1
a
=
1
(b)
b
=
2
b = 2
b
=
2
(c)
c
=
1
2
c = \frac{1}{2}
c
=
2
1
(d)
d
∈
R
d \in R
d
∈
R
(a)
a
=
1
a = 1
a
=
1
(b)
b
=
2
b = 2
b
=
2
(c)
c
=
1
2
c = \frac{1}{2}
c
=
2
1
(d)
d
∈
R
d \in R
d
∈
R
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