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Mathematics
Mathematics
Problem
The curve
r
=
2
sin
2
θ
r=2\sin 2\theta
r
=
2
sin
2
θ
is given in polar form. What is the equation of the normal line to the curve at
θ
=
π
4
\theta=\dfrac{\pi}{4}
θ
=
4
π
? a)
y
=
−
x
+
2
2
y=-x+2\sqrt{2}
y
=
−
x
+
2
2
b)
y
=
x
+
2
2
y=x+2\sqrt{2}
y
=
x
+
2
2
c)
y
=
x
y=x
y
=
x
d)
y
=
−
x
y=-x
y
=
−
x
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