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Problem
Problem
If
[
x
]
2
+
[
x
−
2
]
<
0
[x]^2+[x-2]<0
[
x
]
2
+
[
x
−
2
]
<
0
and
{
x
}
=
1
2
\{x\}=\frac{1}{2}
{
x
}
=
2
1
then the number of possible values of
x
x
x
, is Note:
[
x
]
[x]
[
x
]
and
{
x
}
\{x\}
{
x
}
denote greatest integer less than or equal to
x
x
x
and fractional part of
x
x
x
respectively. (a) 4 (b) 3 (c) 2 (d) 1
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