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Mathematics
Mathematics
Problem
A bacterial culture grows with growth constant
k
=
0.40
hr
−
1
k=0.40\,\text{hr}^{-1}
k
=
0.40
hr
−
1
for the first 3 hours and then decays with constant
k
=
−
0.30
hr
−
1
k=-0.30\,\text{hr}^{-1}
k
=
−
0.30
hr
−
1
thereafter. If
N
(
0
)
=
200
N(0)=200
N
(
0
)
=
200
, calculate
N
(
5
)
N(5)
N
(
5
)
.
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