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Mathematics
Problem
Let
f
f
f
&
g
g
g
be differentiable functions satisfying
g
′
(
m
)
=
4
g'(m) = 4
g
′
(
m
)
=
4
&
g
(
m
)
=
b
g(m) = b
g
(
m
)
=
b
&
f
∘
g
(
x
)
f \circ g(x)
f
∘
g
(
x
)
be an identity function then
f
′
(
b
)
f'(b)
f
′
(
b
)
is - (A) 4 (B)
4
/
3
4/3
4/3
(C)
1
/
4
1/4
1/4
(D)
3
/
4
3/4
3/4
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