Mathematics

Mathematics

Problem

Let CC be the circle of minimum area enclosing the ellipse E:x2a2+y2b2=1E: \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 with eccentricity 12\frac{1}{2} and foci (±2,0)(\pm 2, 0). Let PQR be a variable triangle, whose vertex PP is on the circle CC and the side QRQR of length 29 is parallel to the major axis of EE and contains the point of intersection of EE with the negative yy-axis. Then the maximum area of the triangle PQR is :

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