Mathematical Methods in the Physical Sciences · Problem 5.24

FUNCTIONS OF A COMPLEX VARIABLE — Mary Boas

Mathematics — Methods · parseval-theorem-quantum-mechanics

Problem

Starting with the symmetrized integrals as in Problem 23, make the substitutions α=2πp/h\alpha = 2\pi p/h (where pp is the new variable, hh is a constant), f(x)=ψ(x)f(x) = \psi(x), g(α)=h/2π ϕ(p)g(\alpha) = \sqrt{h/2\pi}\,\phi(p); show that then ψ(x)=1h∫−∞∞ϕ(p)e2πipx/h dp,ϕ(p)=1h∫−∞∞ψ(x)e−2πipx/h dx,∫−∞∞∣ψ(x)∣2 dx=∫−∞∞∣ϕ(p)∣2 dp.\begin{aligned} \psi(x) &= \frac{1}{\sqrt{h}} \int_{-\infty}^{\infty} \phi(p) e^{2\pi i p x/h}\, dp,\\ \phi(p) &= \frac{1}{\sqrt{h}} \int_{-\infty}^{\infty} \psi(x) e^{-2\pi i p x/h}\, dx,\\ \int_{-\infty}^{\infty} |\psi(x)|^2\, dx &= \int_{-\infty}^{\infty} |\phi(p)|^2\, dp. \end{aligned} This notation is often used in quantum mechanics.

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