16.-Linear-Algebra-by-Kenneth-Hoffman · Problem 1.6.12

Systems of Linear Equations

Mathematics — Linear Algebra · hilbert-matrix-invertibility

Problem

The result of Example 16 suggests that perhaps the matrix A=[112⋯1n1213⋯1n+1⋮⋮⋮1n1n+1⋯12n−1]A = \begin{bmatrix} 1 & \frac{1}{2} & \cdots & \frac{1}{n} \\ \frac{1}{2} & \frac{1}{3} & \cdots & \frac{1}{n+1} \\ \vdots & \vdots & & \vdots \\ \frac{1}{n} & \frac{1}{n+1} & \cdots & \frac{1}{2n-1} \end{bmatrix} is invertible and A−1A^{-1} has integer entries. Can you prove that?

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