Problem

Problem

Statement I x=kπ13,k∈Ix = \frac{k\pi}{13}, k \in I does not represent the general solution of trigonometric equation. sin⁡13x−sin⁡13xcos⁡2x=0\sin 13x - \sin 13x \cos 2x = 0 Statement II Both x=rπ,r∈Ix = r\pi, r \in I and x=kπ13,k∈Ix = \frac{k\pi}{13}, k \in I satisfies the trigonometric equation. sin⁡13x−sin⁡13xcos⁡2x=0\sin 13x - \sin 13x \cos 2x = 0

Browse the problem library