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Mathematics
Mathematics
Problem
The region in the first quadrant bounded above by
y
=
1
x
2
+
1
y=\dfrac{1}{x^{2}+1}
y
=
x
2
+
1
1
and below by
y
=
1
(
x
+
1
)
2
y=\dfrac{1}{(x+1)^{2}}
y
=
(
x
+
1
)
2
1
for
x
≥
0
x\ge 0
x
≥
0
is finite. Determine its exact area. a)
π
2
+
1
\dfrac{\pi}{2}+1
2
π
+
1
b)
π
−
1
\pi-1
π
−
1
c)
π
2
−
1
\dfrac{\pi}{2}-1
2
π
−
1
d) Diverges; the area is infinite
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