Mathematics

Problem

Determine the general solution of

\tan \theta = \sqrt{3}

(where

n

is any integer). a)

\theta = 2n\pi \pm \dfrac{\pi}{3}

\theta = n\pi + \dfrac{2\pi}{3}

\theta = n\pi + \dfrac{\pi}{3}

\theta = \dfrac{n\pi}{3}