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Mathematics
Problem
In a
Δ
A
B
C
\Delta ABC
Δ
A
B
C
, the minimum value of
sec
2
A
2
+
sec
2
B
2
+
sec
2
C
2
\sec^2 \frac{A}{2} + \sec^2 \frac{B}{2} + \sec^2 \frac{C}{2}
sec
2
2
A
+
sec
2
2
B
+
sec
2
2
C
is equal to a. 3 b. 4 c. 5 d. 6
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