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Mathematics
Mathematics
Problem
Answer the following (internal choice): a. If
1
−
x
2
+
1
−
y
2
=
a
(
x
−
y
)
\sqrt{1-x^2} + \sqrt{1-y^2} = a(x-y)
1
−
x
2
+
1
−
y
2
=
a
(
x
−
y
)
, then prove that
d
y
d
x
=
1
−
y
2
1
−
x
2
\frac{dy}{dx} = \sqrt{\frac{1-y^2}{1-x^2}}
d
x
d
y
=
1
−
x
2
1
−
y
2
. b. If
x
=
a
(
cos
θ
+
log
tan
θ
2
)
x = a \left( \cos \theta + \log \tan \frac{\theta}{2} \right)
x
=
a
(
cos
θ
+
lo
g
tan
2
θ
)
and
y
=
sin
θ
y = \sin \theta
y
=
sin
θ
, then find
d
2
y
d
x
2
\frac{d^2 y}{dx^2}
d
x
2
d
2
y
at
θ
=
π
4
\theta = \frac{\pi}{4}
θ
=
4
π
.
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