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Mathematics
Mathematics
Problem
If
tan
θ
+
sin
θ
=
m
\tan \theta + \sin \theta = m
tan
θ
+
sin
θ
=
m
and
tan
θ
−
sin
θ
=
n
\tan \theta - \sin \theta = n
tan
θ
−
sin
θ
=
n
, then
(
m
2
−
n
2
)
2
(m^2 - n^2)^2
(
m
2
−
n
2
)
2
is a.
4
m
n
4\sqrt{mn}
4
mn
b.
4
m
n
4mn
4
mn
c.
16
m
n
16\sqrt{mn}
16
mn
d.
16
m
n
16mn
16
mn
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