Chemistry

Problem

For the second step of a reaction mechanism, the following energies are measured relative to the reactant of that step (an intermediate formed earlier): • Energy of intermediate (reactant for step 2): 15 kJ • Energy of transition state: 65 kJ The enthalpy change for step 2 is ΔH₂ = −45 kJ. What is the activation energy for the reverse of step 2? a)

50\;\text{kJ}

110\;\text{kJ}

95\;\text{kJ}

20\;\text{kJ}

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