Mathematics

Mathematics

Problem

For the curve C:(x2+y2−3)+(x2−y2−1)5=0C: (x^2 + y^2 - 3) + (x^2 - y^2 - 1)^5 = 0 , the value of 3y′−y3y′′3y' - y^3y'' , at the point (α,α)(\alpha, \alpha) , α>0\alpha > 0 , on CC , is equal to \_\_\_\_\_\_. [JEE MAINS - ONLINE - 2022]

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