Mathematics — Graph Theory · multigraph-average-neighbor-degree
Problem
Let G=(V,E,φ) be a multigraph that has no loops.
If e∈E is an edge that contains a vertex v∈V, then we let e/v denote the endpoint of e distinct from v.
For each v∈V, we define a rational number qv by
qv=e∈E;v∈φ(e)∑degvdeg(e/v).
(Note that the denominator degv on the right hand side is nonzero whenever the sum is nonempty!)
(Thus, qv is the average degree of the neighbors of v, weighted with the number of edges that join v to the respective neighbors. If v has no neighbors, then qv=0.)
Prove that
v∈V∑qv≥v∈V∑degv.
(In other words, in a social network, your average friend has, on average, more friends than you do!)
[Hint: Any positive reals x and y satisfy yx+xy≥2. Why, and how does this help?]