Grinberg-Introduction-Graph-Theory · Problem 3.5

Multigraphs

Mathematics — Graph Theory · multigraph-average-neighbor-degree

Problem

Let G=(V,E,φ)G = (V, E, \varphi) be a multigraph that has no loops. If e∈Ee \in E is an edge that contains a vertex v∈Vv \in V, then we let e/ve/v denote the endpoint of ee distinct from vv. For each v∈Vv \in V, we define a rational number qvq_v by qv=∑e∈E;v∈φ(e)deg⁡(e/v)deg⁡v.q_v = \sum_{\substack{e \in E;\\ v \in \varphi(e)}} \frac{\deg(e/v)}{\deg v}. (Note that the denominator deg⁡v\deg v on the right hand side is nonzero whenever the sum is nonempty!) (Thus, qvq_v is the average degree of the neighbors of vv, weighted with the number of edges that join vv to the respective neighbors. If vv has no neighbors, then qv=0q_v = 0.) Prove that ∑v∈Vqv≥∑v∈Vdeg⁡v.\sum_{v \in V} q_v \geq \sum_{v \in V} \deg v. (In other words, in a social network, your average friend has, on average, more friends than you do!) [Hint: Any positive reals xx and yy satisfy xy+yx≥2\dfrac{x}{y} + \dfrac{y}{x} \geq 2. Why, and how does this help?]

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