A mixture of phosphorus(III) chloride, phosphorus(V) chloride and chlorine in a sealed flask with a total volume of 2 dm3 was analysed and found to contain 1.2 mol of PCl3, 2.5 mol of PCl5 and 0.2 mol of Cl2.
The equation for the reaction is as follows:
PCl3(g)+Cl2(g)⇌PCl5(g)