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Mathematics
Mathematics
Problem
Given
cos
θ
=
−
3
2
\cos\theta=-\dfrac{\sqrt3}{2}
cos
θ
=
−
2
3
with
θ
∈
(
π
,
3
π
2
)
\theta\in(\pi,\,\tfrac{3\pi}{2})
θ
∈
(
π
,
2
3
π
)
, calculate
sin
θ
\sin\theta
sin
θ
. a)
1
2
\dfrac12
2
1
b)
−
3
2
-\dfrac{\sqrt3}{2}
−
2
3
c)
−
1
2
-\dfrac12
−
2
1
d)
−
2
2
-\dfrac{\sqrt2}{2}
−
2
2
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