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Mathematics
Problem
Explain briefly why the definite integral
∫
1
5
f
(
x
)
d
x
\displaystyle\int_{1}^{5} f(x)\,dx
∫
1
5
f
(
x
)
d
x
exists when
f
(
x
)
=
{
x
2
−
9
x
−
3
,
x
≠
3
,
undefined
,
x
=
3.
f(x)=\begin{cases}\dfrac{x^{2}-9}{x-3}, & x\neq 3,\\ \text{undefined}, & x=3. \end{cases}
f
(
x
)
=
⎩
⎨
⎧
x
−
3
x
2
−
9
,
undefined
,
x
=
3
,
x
=
3.
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