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Mathematics
Mathematics
Problem
If
a
,
b
,
c
a, b, c
a
,
b
,
c
and
d
d
d
are the position vector of the vertices of a cyclic quadrilateral
A
B
C
D
ABCD
A
B
C
D
, prove that
a
×
b
+
b
×
d
+
d
×
a
(
b
−
a
)
⋅
(
d
−
a
)
+
b
×
c
+
c
×
d
+
d
×
b
(
b
−
c
)
⋅
(
d
−
c
)
=
0
\frac{a \times b + b \times d + d \times a}{(b-a) \cdot (d-a)} + \frac{b \times c + c \times d + d \times b}{(b-c) \cdot (d-c)} = 0
(
b
−
a
)
⋅
(
d
−
a
)
a
×
b
+
b
×
d
+
d
×
a
+
(
b
−
c
)
⋅
(
d
−
c
)
b
×
c
+
c
×
d
+
d
×
b
=
0
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