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Chemistry
Chemistry
Problem
The
2
p
2p
2
p
electrons of oxygen (
Z
=
8
Z = 8
Z
=
8
) and fluorine (
Z
=
9
Z = 9
Z
=
9
) are, on average, the same distance
3.5
×
10
−
11
m
3.5 \times 10^{-11}\,\text{m}
3.5
×
1
0
−
11
m
from the nucleus. Assuming the shielding experienced by these electrons is identical, calculate the ratio
I
E
1
(
F
)
I
E
1
(
O
)
\dfrac{IE_{1}(\text{F})}{IE_{1}(\text{O})}
I
E
1
(
O
)
I
E
1
(
F
)
.
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