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Mathematics
Mathematics
Problem
Area of the loop described as
x
=
t
3
(
6
−
t
)
,
y
=
t
2
8
(
6
−
t
)
x = \frac{t}{3}(6-t), y = \frac{t^2}{8}(6-t)
x
=
3
t
(
6
−
t
)
,
y
=
8
t
2
(
6
−
t
)
is a.
27
5
\frac{27}{5}
5
27
b.
24
5
\frac{24}{5}
5
24
c.
27
6
\frac{27}{6}
6
27
d.
21
5
\frac{21}{5}
5
21
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