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Mathematics
Mathematics
Problem
If
a
+
b
tan
θ
=
sec
θ
a + b \tan \theta = \sec \theta
a
+
b
tan
θ
=
sec
θ
and
b
−
a
tan
θ
=
3
sec
θ
b - a \tan \theta = 3 \sec \theta
b
−
a
tan
θ
=
3
sec
θ
, then find the value of
a
2
+
b
2
a^2 + b^2
a
2
+
b
2
.
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