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Mathematics
Mathematics
Problem
If
y
=
tan
−
1
(
1
+
x
2
−
1
x
)
y = \tan^{-1} \left( \frac{\sqrt{1+x^2}-1}{x} \right)
y
=
tan
−
1
(
x
1
+
x
2
−
1
)
, then find
d
y
d
x
\frac{dy}{dx}
d
x
d
y
when
−
1
≤
x
≤
1
-1 \le x \le 1
−
1
≤
x
≤
1
.
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