Lebl-Basic-Analysis-I · Problem 3.4.12

Continuous Functions

Mathematics · uniform-continuity

Problem

Prove: a) If f:S→Rf : S \to \mathbb{R} and g:S→Rg : S \to \mathbb{R} are Lipschitz, then h:S→Rh : S \to \mathbb{R} given by h(x):=f(x)+g(x)h(x) := f(x) + g(x) is Lipschitz. b) If f:S→Rf : S \to \mathbb{R} is Lipschitz and a∈Ra \in \mathbb{R}, then h:S→Rh : S \to \mathbb{R} given by h(x):=af(x)h(x) := af(x) is Lipschitz.

Related theory

Browse the problem library