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Lebl-Basic-Analysis-I
· Problem 3.4.12
Continuous Functions
Mathematics · uniform-continuity
Problem
Prove: a) If
f
:
S
→
R
f : S \to \mathbb{R}
f
:
S
→
R
and
g
:
S
→
R
g : S \to \mathbb{R}
g
:
S
→
R
are Lipschitz, then
h
:
S
→
R
h : S \to \mathbb{R}
h
:
S
→
R
given by
h
(
x
)
:
=
f
(
x
)
+
g
(
x
)
h(x) := f(x) + g(x)
h
(
x
)
:=
f
(
x
)
+
g
(
x
)
is Lipschitz. b) If
f
:
S
→
R
f : S \to \mathbb{R}
f
:
S
→
R
is Lipschitz and
a
∈
R
a \in \mathbb{R}
a
∈
R
, then
h
:
S
→
R
h : S \to \mathbb{R}
h
:
S
→
R
given by
h
(
x
)
:
=
a
f
(
x
)
h(x) := af(x)
h
(
x
)
:=
a
f
(
x
)
is Lipschitz.
Related theory
uniform-continuity
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