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Chemistry
Chemistry
Problem
A sealed flask of volume
3
dm
3
3 \text{ dm}^3
3
dm
3
at temperature
T
T
T
at equilibrium was found to contain 1 mol of
PCl
3
\text{PCl}_3
PCl
3
, 2 mol of
PCl
5
\text{PCl}_5
PCl
5
and 1.5 mol of
Cl
2
\text{Cl}_2
Cl
2
. The equation for the reaction is as follows:
PCl
3
(
g
)
+
Cl
2
(
g
)
⇌
PCl
5
(
g
)
\text{PCl}_3(\text{g}) + \text{Cl}_2(\text{g}) \rightleftharpoons \text{PCl}_5(\text{g})
PCl
3
(
g
)
+
Cl
2
(
g
)
⇌
PCl
5
(
g
)
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