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Mathematics
Problem
[
sin
(
tan
−
1
3
4
)
]
2
=
\left[\sin\left(\tan^{-1}\frac{3}{4}\right)\right]^2 =
[
sin
(
tan
−
1
4
3
)
]
2
=
(a)
3
5
\frac{3}{5}
5
3
(b)
5
3
\frac{5}{3}
3
5
(c)
9
25
\frac{9}{25}
25
9
(d)
25
9
\frac{25}{9}
9
25
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