Physics

Physics

Problem

A pendulum made of a uniform wire of cross sectional area A has time period T. When an additional mass M is added to its bob, the time period changes to TMT_M . If the Young's modulus of the material of the wire is Y then 1Y\frac{1}{Y} is equal to: ( g=gravitational accelerationg = \text{gravitational acceleration} ) [Main 2015] a. [1−(TMT)2]AMg\left[ 1 - \left( \frac{T_M}{T} \right)^2 \right] \frac{A}{Mg} b. [1−(TTM)2]AMg\left[ 1 - \left( \frac{T}{T_M} \right)^2 \right] \frac{A}{Mg} c. [(TMT)2−1]AMg\left[ \left( \frac{T_M}{T} \right)^2 - 1 \right] \frac{A}{Mg} d. [(TMT)2−1]MgA\left[ \left( \frac{T_M}{T} \right)^2 - 1 \right] \frac{Mg}{A}

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