A Modern Approach to Quantum Mechanics · Problem 1.6

Rotation of Basis States and Matrix Mechanics — John S. Townsend

Physics — Quantum Mechanics · spin-half-orthogonality

Problem

Show that the state ∣−n⟩=sin⁡θ2∣+z⟩−eiϕcos⁡θ2∣−z⟩|{-}\mathbf{n}\rangle = \sin\frac{\theta}{2}|{+}\mathbf{z}\rangle - e^{i\phi}\cos\frac{\theta}{2}|{-}\mathbf{z}\rangle satisfies ⟨+n∣−n⟩=0\langle{+}\mathbf{n}|{-}\mathbf{n}\rangle = 0, where the state ∣+n⟩|{+}\mathbf{n}\rangle is given in Problem 1.3. Verify that ⟨−n∣−n⟩=1\langle{-}\mathbf{n}|{-}\mathbf{n}\rangle = 1.

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