Physics

Problem

An object is placed

40\,\text{cm}

in front of a concave mirror of focal length

20\,\text{cm}

. Using the Cartesian sign convention, the image distance

v

is: a)

+\dfrac{40}{3}\,\text{cm}

-40\,\text{cm}

+40\,\text{cm}

-20\,\text{cm}