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Mathematics
Problem
If the line
x
−
1
2
=
y
+
1
3
=
z
−
1
4
\frac{x-1}{2} = \frac{y+1}{3} = \frac{z-1}{4}
2
x
−
1
=
3
y
+
1
=
4
z
−
1
and
x
−
3
1
=
y
−
k
2
=
z
1
\frac{x-3}{1} = \frac{y-k}{2} = \frac{z}{1}
1
x
−
3
=
2
y
−
k
=
1
z
intersect, then
k
k
k
is equal to a.
−
1
-1
−
1
b.
2
9
\frac{2}{9}
9
2
c.
9
2
\frac{9}{2}
2
9
d.
0
0
0
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