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Mathematics
Problem
Let
a
a
a
be the first term and
r
r
r
the common ratio (
∣
r
∣
<
1
|r|<1
∣
r
∣
<
1
) of a convergent geometric progression. The sum of the first
n
n
n
terms is
S
n
S_n
S
n
and the sum to infinity is
S
∞
S_{\infty}
S
∞
. a. (i) Prove that
S
n
=
a
(
1
−
r
n
)
1
−
r
S_n = \dfrac{a(1-r^{\,n})}{1-r}
S
n
=
1
−
r
a
(
1
−
r
n
)
.},{
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