If Δ=∣a11a12a13a21a22a23a31a32a33∣\Delta = \begin{vmatrix} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33} \end{vmatrix}…

Mathematics

Problem

If Δ=∣a11a12a13a21a22a23a31a32a33∣\Delta = \begin{vmatrix} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33} \end{vmatrix} and Cij=(−1)i+jMijC_{ij} = (-1)^{i+j} M_{ij}, where MijM_{ij} is a determinant obtained by deleting ii th row and jj th column, then ∣C11C12C13C21C22C23C31C32C33∣=Δ2\begin{vmatrix} C_{11} & C_{12} & C_{13} \\ C_{21} & C_{22} & C_{23} \\ C_{31} & C_{32} & C_{33} \end{vmatrix} = \Delta^2. If ∣1xx2xx21x21x∣=5\begin{vmatrix} 1 & x & x^2 \\ x & x^2 & 1 \\ x^2 & 1 & x \end{vmatrix} = 5 and Δ=∣x3−10x−x40x−x4x3−1x−x4x3−10∣\Delta = \begin{vmatrix} x^3 - 1 & 0 & x - x^4 \\ 0 & x - x^4 & x^3 - 1 \\ x - x^4 & x^3 - 1 & 0 \end{vmatrix}, then sum of digits of Δ2\Delta^2 is a. 7 b. 8 c. 13 d. 11

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