Chemistry

Chemistry

Problem

Calculate the standard enthalpy change ΔH∘\Delta H^{\circ} for the reaction representing photosynthesis: 6CO2(g)+6H2O(l)→C6H12O6(s)+6O2(g)6\text{CO}_2(g)+6\text{H}_2\text{O}(l)\rightarrow \text{C}_6\text{H}_{12}\text{O}_6(s)+6\text{O}_2(g) Data: ΔHf∘(CO2(g))=−393.5 kJ mol−1\Delta H_f^{\circ}(\text{CO}_2\text{(g)}) = -393.5\,\text{kJ mol}^{-1} ΔHf∘(H2O(l))=−285.8 kJ mol−1\Delta H_f^{\circ}(\text{H}_2\text{O}(l)) = -285.8\,\text{kJ mol}^{-1} ΔHf∘(C6H12O6(s))=−1273 kJ mol−1\Delta H_f^{\circ}(\text{C}_6\text{H}_{12}\text{O}_6(s)) = -1273\,\text{kJ mol}^{-1} a) +1.3×103 kJ+1.3\times10^{3}\,\text{kJ} b) −2.8×103 kJ-2.8\times10^{3}\,\text{kJ} c) +2.8×103 kJ+2.8\times10^{3}\,\text{kJ} d) −5.9×102 kJ-5.9\times10^{2}\,\text{kJ}

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