Problem

Problem

If sin⁡3α=4sin⁡αsin⁡(x+α)sin⁡(x−α)\sin 3\alpha = 4 \sin \alpha \sin(x + \alpha) \sin(x - \alpha) , then a. x=nπ±π3,n∈Ix = n\pi \pm \frac{\pi}{3}, n \in I b. x=nπ±π6,n∈Ix = n\pi \pm \frac{\pi}{6}, n \in I c. x=nπ±π2,n∈Ix = n\pi \pm \frac{\pi}{2}, n \in I d. None of the above

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