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Mathematics
Mathematics
Problem
If
4
cot
θ
=
5
4 \cot \theta = 5
4
cot
θ
=
5
, show that:
5
sin
θ
+
3
cos
θ
5
sin
θ
−
2
cos
θ
=
7
2
\frac{5 \sin \theta + 3 \cos \theta}{5 \sin \theta - 2 \cos \theta} = \frac{7}{2}
5
s
i
n
θ
−
2
c
o
s
θ
5
s
i
n
θ
+
3
c
o
s
θ
=
2
7
.
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