Mathematics

Mathematics

Problem

Let f(x)=(3x−4)2+5f(x)=(3x-4)^{2}+5 on the closed interval [0,3][0,3]. Which value of xx yields the absolute minimum of ff on this interval? a) x=0x=0 b) x=43x=\dfrac{4}{3} c) x=23x=\dfrac{2}{3} d) x=2x=2

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