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Mathematics
Mathematics
Problem
If
x
3
−
2
x
2
y
2
+
5
x
+
y
−
5
=
0
x^3 - 2x^2 y^2 + 5x + y - 5 = 0
x
3
−
2
x
2
y
2
+
5
x
+
y
−
5
=
0
and
y
(
1
)
=
1
y(1) = 1
y
(
1
)
=
1
, then (a)
y
′
(
1
)
=
4
/
3
y'(1) = 4/3
y
′
(
1
)
=
4/3
(b)
y
′
′
(
1
)
=
−
4
/
3
y''(1) = -4/3
y
′′
(
1
)
=
−
4/3
(c)
y
′
′
(
1
)
=
−
8
22
27
y''(1) = -8 \frac{22}{27}
y
′′
(
1
)
=
−
8
27
22
(d)
y
′
(
1
)
=
2
/
3
y'(1) = 2/3
y
′
(
1
)
=
2/3
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