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Problem
Problem
For a cell, the terminal potential difference is 2.2 V, when circuit is open and reduces to 1.8 V. When cell is connected to a resistance
R
=
5
Ω
R = 5 \Omega
R
=
5Ω
, the internal resistance of cell (
r
r
r
) is (a)
10
9
Ω
\frac{10}{9} \Omega
9
10
Ω
(b)
9
10
Ω
\frac{9}{10} \Omega
10
9
Ω
(c)
11
9
Ω
\frac{11}{9} \Omega
9
11
Ω
(d)
5
9
Ω
\frac{5}{9} \Omega
9
5
Ω
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