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Problem
Problem
Solve the equation
log
(
x
2
−
1
)
(
x
3
+
6
)
=
log
(
x
2
−
1
)
(
2
x
2
+
5
x
)
.
\log_{(x^2-1)} (x^3+6) = \log_{(x^2-1)} (2x^2+5x).
lo
g
(
x
2
−
1
)
(
x
3
+
6
)
=
lo
g
(
x
2
−
1
)
(
2
x
2
+
5
x
)
.
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